I checked em all they were right "Daniel Clark" <dclark@xxxxxxxxxx> wrote in message news:18323.65.203.232.102.1087951969.squirrel@xxxxxxxxxxxxxxxxxxxxxxx > Sounds like it doesn't like your SQL statement. Perhaps a field or table > name is incorrect? > > > Warning: mysql_fetch_array(): supplied argument is not a valid MySQL > > result > > resource in ....... > > "Daniel Clark" <dclark@xxxxxxxxxx> wrote in message > > news:16692.65.203.232.102.1087950853.squirrel@xxxxxxxxxxxxxxxxxxxxxxx > >> What error are you getting? > >> > >> > why doesn't this work: > >> > $pic=mysql_query('SELECT Rune, username FROM RuneRunner > >> > RuneRunner_1 WHERE (User_ID = 3)',$connection); > >> > $pic=mysql_fetch_array($pic); -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
