Re: problem....

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Sounds like it doesn't like your SQL statement.  Perhaps a field or table
name is incorrect?

> Warning: mysql_fetch_array(): supplied argument is not a valid MySQL
> result
> resource in .......
> "Daniel Clark" <dclark@xxxxxxxxxx> wrote in message
> news:16692.65.203.232.102.1087950853.squirrel@xxxxxxxxxxxxxxxxxxxxxxx
>> What error are you getting?
>>
>> > why doesn't this work:
>> > $pic=mysql_query('SELECT     Rune, username FROM         RuneRunner
>> > RuneRunner_1 WHERE     (User_ID = 3)',$connection);
>> > $pic=mysql_fetch_array($pic);

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