assigning variables after one-to-many query

[Rachel Rodriguez <email2rachel2003@xxxxxxxxx>]

Hi!

I have a one-to-many relationship between two tables
(table1 and table3) with a "linking" table between
them (table2):

table1:          table2          
+---+--------+   +---+--------+  
|id | f_name |   |id | emailID|  
+---+--------+   +---+--------+  
| 1 | bill   |   | 1 |   1    |  
| 2 | john   |   | 1 |   4    |  
| 3 | diana  |   | 1 |   3    |  
| 4 | victor |   | 2 |   2    |  
| 5 | renata |   | 4 |   5    |  
+---+--------+   +---+--------+  

table3
+--------+-----------------+
|emailID | email           | 
+--------+-----------------+
|   1    | bill@xxxxxxxxxxx|
|   2    | diana@xxxxxxxxx |   
|   3    | bill@xxxxxxxxx  |
|   4    | bill@xxxxxxxxxx |
|   5    | vic@xxxxxxxxxxx | 
+--------+-----------------+

I would like to write a query that matches table1.id
with records
from table3.emailID via the linking table (table2) and
then 
assign each match to a variable.

Here is what I have:

$query = "SELECT t3.email
          FROM   table3 AS t3
          LEFT JOIN table2 AS t2
          ON (t3.emailID = t2.emailID)
          LEFT JOIN table1 AS t1
          ON (t2.id = t1.id)
          WHERE t1.id = 1";

$result = @myql_query($query, $db_connection);

$num = mysql_num_rows($result);

$email1 = "";
$email2 = "";
$email3 = "";

if ($num > 0)
{
    while ($row = mysql_fetch_array($result))
    {
       // do something here to assign
       // $email1 = $row[email] and 
       // $email2 = $row[email], etc.
    }
}

Of course, the problem I am having is as I am going
through the "while" loop, I am assigning $email1,
$email2, and so on the 

same e-mail address.

I would like to get: $email1 = bill@xxxxxxxxxxx,
$email2 = bill@xxxxxxxxxx, and $email3 =
bill@xxxxxxxxxx

I would prefer to do that rather than what I have seen
in most examples which is similar to the following:

// snippet of code

     while ($row = mysql_fetch_array($result))
     {
          echo"Bill's email is $row[email].";
     }

// end of snippet

Any assistance is greatly appreciated.

Thanks,
Rachel


	
		
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