there are many ways to approach this.
one is, select the db before any of this activity with mysql_select_db
("dbname") then you can run as many queries against this database as you
want.
Until you call that function again with another db name, mysql with
_always_ run against that database.
hth
jd
Michael Cortes
<cortesm@fortlebo To: php-db@lists.php.net
euf.net> cc:
Subject: Don't know why query works this way
08/05/2003 11:35
PM
Please respond to
cortesm
I have been writing my queries like this.......
$link = mysql_connect ($host, $username, $password);
$query = "insert into $table ('joe', 15)";
if ( mysql_db_query($dbname, $query, $link)) { }
But then I was reading that I should use mysl_query instead of
mysql_db_query.
But I was having a problem with where do i put the $dbname.
When I used:
mysql_query ($dbname, $query, $link)
I got an error message saying i had too many arguments. So I changed it
to:
mysql_query ($query, $link)
I then got an error message saying it didn't know what database I was
connected to. I finally got around the problem by including the database
name in the query, like so:
$query = "insert into $dbname.$table ('joe', 15)";
I shouldn't have to say, but this is a simplified example. I didn't want
to
include all the fields, tables, values that the true example has. The
question is, am I doing this right? Do I have no choice but to retype the
$dbname all over the place if I want to use "mysql_query"?
Thank in advance for any help.
--
Michael Cortes
Fort LeBoeuf School District
34 East Ninth Street
PO Box 810
Waterford PA 16441-0810
814.796.4795
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