Re: Re: Now, how about Roman Numerals?

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"Richard Hutchins" <Richard.Hutchins@Getingeusa.com> wrote in message
1EA7D3AE70ACD511BE6D006097A78C1E033C8F9A@USROCEXC">news:1EA7D3AE70ACD511BE6D006097A78C1E033C8F9A@USROCEXC...
> Here's a rundown of what the script is doing based on your input:
>
> If you pass in the number 155, here are the calculations:
>$m = $num / 1000; //$m will be equal to .155
>$c = ($num % 1000) / 100; //$c will be equal to 1.55
>$x = ($num % 100) / 10; //$x will be equal to 5.5
>$i = $num % 10; //$i will be equal to 5
>[snip]

Yes, that's exactly the problem... I assumed
integer-only input and casting.  Here is a fixed
(tested) version:


<?php

function RomanDigit($dig, $one, $five, $ten) {
  switch($dig) {
      case 0:    return "";
      case 1:    return "$one";
      case 2:    return "$one$one";
      case 3:    return "$one$one$one";
      case 4:    return "$one$five";
      case 5:    return "$five";
      case 6:    return "$five$one";
      case 7:    return "$five$one$one";
      case 8:    return "$five$one$one$one";
      case 9:    return "$one$ten";
  }
}

function IntToRoman($num) {
  $num = (int) $num;
  if (($num < 1) || ($num > 3999))
      return("No corresponding Roman number!");

  $m = (int) ($num * 0.001);          $num -= $m*1000;
  $c = (int) ($num * 0.01);           $num -= $c*100;
  $x = (int) ($num * 0.1);            $num -= $x*10;
  $i = (int) ($num);

// echo "m = $m, c = $c, x = $x, i = $i   ";

  return(
       RomanDigit($m, 'M', '', '')
      . RomanDigit($c, 'C', 'D', 'M')
      . RomanDigit($x, 'X', 'L', 'C')
      . RomanDigit($i, 'I', 'V', 'X')
  );
}

?>


and my test script:

<?php

include("to_roman.php");

$test = array( 8, 19, 155, 980, 9.8, -3, 3999, 4000, "abc", "", array() );

foreach($test as $num)
    echo "$num =&gt; ".IntToRoman($num)."<br/>";

?>


--
Hugh Bothwell     hugh_bothwell@hotmail.com     Kingston ON Canada
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