Hi David,
Try this one:
<?
function formatDate($val)
{
setlocale (LC_ALL, '');
$arr = explode("-", $val);
return strftime ("%A %e %B %Y", mktime (0, 0, 0, $arr[1], $arr[2],
$arr[0]));
}
echo formatDate($DatePick);
?>
Regards,
Frank
----- Original Message -----
From: "David Shugarts" <Azimuth@CompuServe.com>
To: <php-db@lists.php.net>
Sent: Tuesday, June 10, 2003 11:23 PM
Subject: Date Formatting in PHP
>
>
>
> I have a simple need to reformat a variable coming in as $DatePick,
brought
> forward from a MySQL select in the format:
>
> 2003-11-18
>
> I need to convert it to the format
>
> November 18, 2003
>
> I am trying to avoid having to mess with the MySQL select statement, as
the
> output is being passed through several documents. So I need to do it
within
> PHP.
>
> I tried making a conversion like
>
> $DayReport = date ("F d, Y", $DatePick);
>
> But the value of $DayReport is neither correct nor does it change when
> $DatePick changes. For instance, in this example, the $DatePick value of
> "2003-11-18" gets converted to "December 31, 1969."
>
> TIA
>
> Dave Shugarts
>
>
>
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