ok, let me see if i understand what your saying.... so for $_POST['copy'] I have to go.... $myrow['copy'] = $_POST['copy'] ? "Matt Schroebel" <MSchroebel@hsus.org> wrote in message D4DB668A680B2549AE977FB0B193E2E86DD7D7@email.hsus.org">news:D4DB668A680B2549AE977FB0B193E2E86DD7D7@email.hsus.org... > -----Original Message----- > From: Chris Mach [mailto:cjmach@learn.senecac.on.ca] > Sent: Tuesday, April 22, 2003 3:24 PM > To: php-db@lists.php.net > Subject: Re: php 4.0.5 to php 4.2.2 > > > It's not my server so I don't think i have access to change > the php.ini > file. > > I tried the $_POST["title"] and $HTTP_POST_VARS["title"] and > it worked, > except now it replaces my previous data instead of adding a > new record. > > Is there a way that i can use $_POST in combination with my > array variable > $myrow? > > > http://matrix.senecac.on.ca/~cjmach/test.php You have to find all references to globals that were posted, and change them. Such as $_POST['submit'] and $_POST['copy']. Also you have hard coded values on the values on the insert that you might want to change to something more meaningful. -- PHP Database Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
