Re: mysql if statement to php

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In article <20030414012904.11497.qmail@web41212.mail.yahoo.com>, 
jusa_98@yahoo.com says...
> Hi,
> 
> I am using a php page to grab information using the if
> statement.  Now the mysql query works fine but I can't
> get the output to output into php.  I have tried many
> things and have failed to get it to display.
> 
> This is the code:
> 
> <?php
> mysql_connect ("localhost", "$usr", "$pass") or die
> ('I cannot connect to the database.');
> mysql_select_db ("$db"); 
> 
> $qr = mysql_query("SELECT IF( emailerror = ('y' ),
> 'error yes', 'do nothing' ) FROM tipping WHERE sid =
> '$sid'");
> 
> ?>
> 
> If I do the above query in mysql it returns correctly.
>  If Y is in the table it dispalys error yes.  But how
> do I get it to output to a php page with the above
> function?
> 
> Thanks!
> 
> http://mobile.yahoo.com.au - Yahoo! Mobile
> - Check & compose your email via SMS on your Telstra or Vodafone mobile.
> 
If you take a look at http://au.php.net/mysql_fetch_array you'll find a 
few examples of how to get query results and display them; you may find 
echo easier than the printf used in the examples.


-- 
Quod subigo farinam

$email =~ s/oz$/au/o;


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