Hi
Probably a missing ;
?>
<option value="<? echo $row["0"]; ?>"><? echo $row["1"]; echo
$row["2"]; ?></option>
<?
} ; <--------- here
?>
</select>
</form>
-----Original Message-----
From: Ignatius Reilly [mailto:ignatius.reilly@free.fr]
Sent: 23 January 2003 22:00
To: David Rice; php-db@lists.php.net
Subject: Re: need help spotting this php parse error
Dunno.
I also remember once having a parse error, but it was on line 35.
Cheers
Ignatius
____________________________________________
----- Original Message -----
From: "David Rice" <haloplayer@hotmail.com>
To: <php-db@lists.php.net>
Sent: Thursday, January 23, 2003 8:53 PM
Subject: need help spotting this php parse error
> When i run this script it tells me that I have a parse error on line 34? I
> really can't see it anyhelp (please!) would be much appreciated Cheers,
Dave
>
> <?
>
> session_start();
>
> if(!$HTTP_COOKIE_VARS["username"]) {
>
> /* The Cookie is not set, so load the page as if it is the first time
> */
>
> include("library/include/header.php");
> include("library/include/database.php");
>
> /* Include a header file and a database connections/functions file
> */
>
> ?>
>
> <form name="login" method="post" action="">
> <select name="select">
>
> <?
>
> $query = "SELECT * FROM Staff WHERE ResterauntId = 1";
> $result = mysql_query($query) or die( mysql_error () );
>
> While( $row = mysql_fetch_array($result) ) {
>
> ?>
> <option value="<? echo $row["0"]; ?>"><? echo $row["1"]; echo
> $row["2"]; ?></option>
> <?
> }
> ?>
> </select>
> </form>
>
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