Hmm, I think the following both function calls produces the same result,
were the second one is deprecated.
function foo(&$bar) {
$bar .= " WORLD";
}
$tmp = "HELLO";
foo($tmp);
echo $tmp;
function bar($foo) {
$foo .= " WORLD";
}
$tmp2 = "HELLO";
bar(&$tmp2);
echo $tmp2;
So why not change the deprecated function call to the working one?
If the function calls were only changed from foo(&$var) to foo($var)
the functions will not produce the expected results. They need to be
changed, too!?
Manuel Lemos schrieb:
>
>
> Hello,
>
> on 01/24/2008 01:56 PM Stephan Schulze said the following:
> > You should get the newest version of the class.
> >
> > Or you fix it by replacing all calls with foo(&variable) to
> > foo(variable) and change
>
> That is the problem.
>
> > function foo(variable) to function foo(&variable)
>
> Do not do this. This is not the problem. If you change this, the class
> will not be able to return values to variables passed by reference.
>
> --
>
> Regards,
> Manuel Lemos
>
> PHP professionals looking for PHP jobs
> http://www.phpclasses.org/professionals/
> <http://www.phpclasses.org/professionals/>
>
> PHP Classes - Free ready to use OOP components written in PHP
> http://www.phpclasses.org/ <http://www.phpclasses.org/>
>
>
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