Thanks a lot for your message Jony dos Santos Kostetzer and José Miguel
Santibáñez, actually that @ was my mistake, I got to solve it this way:
function MarkWords($profile_text, $words){
for($i=0; $i<count($words); $i++){
$patern[$i] = "@".$words[$i]."@i";
$replace[$i] = "<span
style='color:white'>".$words[$i]."</span>";
}
$pro = preg_replace($patern, $replace, $profile_text);
return $pro;
}
But I am not happy because if I do this:
$words = array('PEACE','people');
$profile_text = "I would like to meet People to help me to work in the
world Peace project.";
$marked = MarkWords($profile_text, $words);
This will return (marked of course)
"I would like to meet people to help me to work in the world PEACE project."
But I would like to keep the orignal word and change just the color.
Jony dos Santos Kostetzer escreveu:
> Hi Fransciso,
>
> Why did you use @? If you remove it, preg works correctly. If you want
> match
> only complete words, use $patern[$i] = "/\b".$words[$i]."\b/";
>
> Regards from Brazil =D
>
> Jony dos Santos Kostetzer
> A2C Internet - R&D
>
> Em Ter 28 Mar 2006 19:47, Francisco - São Paulo - Brazil escreveu:
> > Suppose I have this:
> >
> > $words = array('piece','people');
> > $profile_text = "I would like to meet people to help me to work in the
> > world piece project.";
> >
> > $marked = MarkWords($profile_text, $words);
> >
> > Should return the same sentece but with the 2 words replaced with the
> > <span> tag, am I wrong?
> >
> > function MarkWords($profile_text, $words){
> > for($i=0; $i<count($words); $i++){
> > $patern[$i] = "/@".$words[$i]."/";
> > $replace[$i] = "<span
> > style='color:white'>".$words[$i]."</span>";
> > }
> > // print_r($patern);
> > // print_r($replace);
> >
> > $pro = preg_replace($patern, $replace, $profile_text);
> > return $pro;
> > }
>
> --
>
>
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