Hi Fransciso,
Why did you use @? If you remove it, preg works correctly. If you want match
only complete words, use $patern[$i] = "/\b".$words[$i]."\b/";
Regards from Brazil =D
Jony dos Santos Kostetzer
A2C Internet - R&D
Em Ter 28 Mar 2006 19:47, Francisco - São Paulo - Brazil escreveu:
> Suppose I have this:
>
> $words = array('piece','people');
> $profile_text = "I would like to meet people to help me to work in the
> world piece project.";
>
> $marked = MarkWords($profile_text, $words);
>
> Should return the same sentece but with the 2 words replaced with the
> <span> tag, am I wrong?
>
> function MarkWords($profile_text, $words){
> for($i=0; $i<count($words); $i++){
> $patern[$i] = "/@".$words[$i]."/";
> $replace[$i] = "<span
> style='color:white'>".$words[$i]."</span>";
> }
> // print_r($patern);
> // print_r($replace);
>
> $pro = preg_replace($patern, $replace, $profile_text);
> return $pro;
> }
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