Actually, that's not true. Globals are available in included files as well. The only problem arises when you use them before assigning a value to the global variable you're using.
On Sat, Jul 27, 2019 at 10:04 PM Jeffry Killen <jekillen@xxxxxxxxxxx> wrote:
> On Jul 27, 2019, at 8:47 PM, LinuxManMikeC <linuxmanmikec@xxxxxxxxx> wrote:
>
> Functions don't automatically have access to global variables. Use the 'global' keyword to declare what global variables you're going to use in your function.
>
> function nav_list() {
> global $auth_array;
> // Code...
> }
>
Also it will make a difference WHERE nav_list is defined:
If it is defined in a separate script file and included or required by
the calling script, it will not have access to $auth_array unless you
define it as an argument to nav_list and pass it in when nav_list is
called.
The only way I know how to make a variable visible without having to
pass it by reference is
class sampleClass
{
private static $test = 'Orange';
public function showTest()
{
return self::$test;
}
}
$test = new samleClass()
print $test->showTest(); // 'Orange'
In your case
function nav_list($arrayArg)
{
// code
}
nav_list($auth_array) //>> assuming this call is made in the scope where $auth_array is defined ready to use.
> https://www.php.net/manual/en/language.variables.scope.php
>
> On Sat, Jul 27, 2019, 19:47 John <john.iliffe@xxxxxxxxx> wrote:
> There is probably another way to do this but I have spent a good few hours
> trying to resolve it and I think there is something wrong with the way I
> understand the scope of variables in PHP, so an answer would be appreciated.
>
> I have a PHP (7.1.3) programme that opens a database during initialization,
> gathers an associative array of variables (pg_fetch_array) and then closes the
> database. The array name is $auth_array. During actual display of the page the
> values of the elements of the array are used to control what is (not) displayed
> and lookup of the values is done using a separate function.
>
> At this point I can print_r() the array and it contains what I expect.
>
> In the next line, I call a user-defined function nav_list() where this array is
> used in the form $auth_array['column name']. At this point I get a PHP error
> "Got error 'PHP message: PHP Notice: Undefined variable: auth_array in
> /httpd/myprogramme/yrarcex.php on line 74\nPHP message: PHP Notice: Undefined
> variable: auth_array .... . At this point I cannot print_r the array, the same
> undefined variable message appears.
>
> I expected that auth_array would be in global scope.
>
> so I tried calling nav_list() with no arguments, then with the name of the array
> as the only argument, and with the address of the array (&$auth_array) and also
> with the explicit cast nav_list(array $auth_array) and I always get the same
> error message. (not a data type error as suggested in the docs).
>
> So far as I can see I am following the online documentation at
>
> https://www.php.net/manual/en/functions.arguments.php
>
> exactly.
>
> The definition of nav_list() is;
>
> function nav_list()
> {
> if ($auth_array['u_....'] == 't') <---- this is line 74 as shown in the error
> {
> // display something
> }
> }
>
>
