Functions don't automatically have access to global variables. Use the 'global' keyword to declare what global variables you're going to use in your function.
function nav_list() {
global $auth_array;
// Code...
}
On Sat, Jul 27, 2019, 19:47 John <john.iliffe@xxxxxxxxx> wrote:
There is probably another way to do this but I have spent a good few hours
trying to resolve it and I think there is something wrong with the way I
understand the scope of variables in PHP, so an answer would be appreciated.
I have a PHP (7.1.3) programme that opens a database during initialization,
gathers an associative array of variables (pg_fetch_array) and then closes the
database. The array name is $auth_array. During actual display of the page the
values of the elements of the array are used to control what is (not) displayed
and lookup of the values is done using a separate function.
At this point I can print_r() the array and it contains what I expect.
In the next line, I call a user-defined function nav_list() where this array is
used in the form $auth_array['column name']. At this point I get a PHP error
"Got error 'PHP message: PHP Notice: Undefined variable: auth_array in
/httpd/myprogramme/yrarcex.php on line 74\nPHP message: PHP Notice: Undefined
variable: auth_array .... . At this point I cannot print_r the array, the same
undefined variable message appears.
I expected that auth_array would be in global scope.
so I tried calling nav_list() with no arguments, then with the name of the array
as the only argument, and with the address of the array (&$auth_array) and also
with the explicit cast nav_list(array $auth_array) and I always get the same
error message. (not a data type error as suggested in the docs).
So far as I can see I am following the online documentation at
https://www.php.net/manual/en/functions.arguments.php
exactly.
The definition of nav_list() is;
function nav_list()
{
if ($auth_array['u_....'] == 't') <---- this is line 74 as shown in the error
{
// display something
}
}
