Hello.
I'm compiling the current PHP 7.3 release from source, and I would like to compile with the latest OpenSSL instead of the system-native OpenSSL.
My understanding is the `--with-openssl` and `--with-openssl-dir` flags are the way forward. When I use both and provide relative directory to OpenSSL source, the PHP compile completes without error, but a subsequent `phpinfo()` check shows the (older) system-native library used instead.
My questions:
* Is it possible to compile PHP 7.3 with OpenSSL source?
* If not, do I need to compile a portable OpenSSL first, then compile PHP with references to said OpenSSL?
* Does using `--with-openssl` and `--with-openssl-dir` together force the system-native version to be used because `--with-openssl` appears before `--with-openssl-dir`?
Thank you in advance for any feedback and advice.
==8<==
Compile script (trimmed for brevity):
opensslsourceversion="1_1_1c" \
&& php73sourceversion="7.3.6" \
&& zlibsourceversion="1.2.11" \
[obtain source archives, extract archives]
&& cd ~/php7.3-source/php-src-php-$php73sourceversion/ \
&& ./buildconf --force \
&& ./configure \
--enable-bcmath \
[various `enable` flags in alphabetical order]
--enable-zip \
--prefix=/etc/php/7.3/ \
--with-config-file-path=/etc/php/7.3/etc/ \
[various `with-*` flags in alphabetical order]
--with-mysqli \
--with-openssl \
--with-openssl-dir=../../openssl-source/openssl-OpenSSL_$opensslsourceversion \
--with-pdo-mysql \
[various `with-*` flags in alphabetical order]
--with-zlib \
--with-zlib-dir=../../zlib-source/zlib-$zlibsourceversion \
&& make clean \
&& make -j$(cat /proc/cpuinfo | grep processor | wc -l) \
&& sudo make install
==8<==
