On 07/18/2015 05:40 AM, German Geek wrote:
What do you actually want to achieve?
On Sat, 18 Jul 2015 at 21:39 German Geek <geek.de@xxxxxxxxx> wrote:
Of course you need to give the variable $someNumber a value.
On Sat, 18 Jul 2015 at 03:45 Ethan Rosenberg <
erosenberg@xxxxxxxxxxxxxxxxxxxx> wrote:
Thanks -
On 07/17/2015 12:34 AM, German Geek wrote:
You cannot run a C program and grab input from PHP interactively! You
would have to pipe the input
in as so:
// untested!
$number = `echo $someNumber | /var/www/TestScanf`;
echo 'number in php<br />';
Also, returning the number num in C's main function is wrong. You
should return 0 if successful and
another int if the program has an error.
<snip>
You cannot run a C program and grab input from PHP interactively! You
would have to pipe the input
in as so:
// untested!
$number = `echo $someNumber | /var/www/TestScanf`;
echo 'number in php<br />';
Also, returning the number num in C's main function is wrong. You should
return 0 if successful and
another int if the program has an error.
CODE
$number = `echo $someNumber | /var/www/TestScanf`;
//$number = `/var/www/TestScanf`;
echo 'number in php<br />';
echo $number;
OUTPUT
Notice: Undefined variable: someNumber in /var/www/Scanf.php on line 36
number in php
Enter your Number 0
TIA
Ethan
---------
Thanks -
> What do you actually want to achieve?
To input an integer into a PHP script, with the number being generated by an external C program.
TIA
Ethan
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