What do you actually want to achieve? On Sat, 18 Jul 2015 at 21:39 German Geek <geek.de@xxxxxxxxx> wrote: > Of course you need to give the variable $someNumber a value. > > On Sat, 18 Jul 2015 at 03:45 Ethan Rosenberg < > erosenberg@xxxxxxxxxxxxxxxxxxxx> wrote: > >> Thanks - >> >> On 07/17/2015 12:34 AM, German Geek wrote: >> > You cannot run a C program and grab input from PHP interactively! You >> would have to pipe the input >> > in as so: >> > >> > // untested! >> > $number = `echo $someNumber | /var/www/TestScanf`; >> > echo 'number in php<br />'; >> > >> > Also, returning the number num in C's main function is wrong. You >> should return 0 if successful and >> > another int if the program has an error. >> > >> > >> > >> <snip> >> >> You cannot run a C program and grab input from PHP interactively! You >> would have to pipe the input >> in as so: >> >> // untested! >> $number = `echo $someNumber | /var/www/TestScanf`; >> echo 'number in php<br />'; >> >> Also, returning the number num in C's main function is wrong. You should >> return 0 if successful and >> another int if the program has an error. >> >> >> CODE >> >> >> $number = `echo $someNumber | /var/www/TestScanf`; >> //$number = `/var/www/TestScanf`; >> echo 'number in php<br />'; >> >> echo $number; >> >> OUTPUT >> >> >> Notice: Undefined variable: someNumber in /var/www/Scanf.php on line 36 >> number in php >> Enter your Number 0 >> >> TIA >> >> Ethan >> >
