Re: PHP output fails from AJAX call

[Date Prev][Date Next][Thread Prev][Thread Next][Date Index][Thread Index]

 



On 30 Jan 2014 at 06:27, Adarsh Sharma <eddy.adarsh@xxxxxxxxx> wrote: 

> Hi,
>
> I am using AJAX and php for creating a small UI that retrieves data from
> mysql upon clicking on one button. But i clicked on that , nothing is
> happening. Below is my index.html :
>
> *-- index.html *
>
> <html>
> <head>

Missing <script ... > as Niklaus has pointed out.

> function week_report_fun(){
> var ajaxRequest;
> ---
> ---
> --
> ajaxRequest.open("GET","ajaxex.php?q="+users,true);

What is "users"? Where is your code to get the selected value from the form?

> ajaxRequest.send();
> }
>
> </script></head><body>
> <form>
> User : <select id="users" onchange="week_report_fun()">
> <option value="">Select a user</option>
> <option value="133">av</option>
> <option value="168">ad</option>
> <option value="78">so</option>
> <option value="239">ak</option>
> </select></form><br>
> <div id="txtHint"><b>Person info will be listed here.</b></div>
> </body></html>

Where is your code to get the returned results from your PHP script and display it?


--
Cheers  --  Tim

-- 
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php

[Index of Archives]     [PHP Home]     [Apache Users]     [PHP on Windows]     [Kernel Newbies]     [PHP Install]     [PHP Classes]     [Pear]     [Postgresql]     [Postgresql PHP]     [PHP on Windows]     [PHP Database Programming]     [PHP SOAP]

  Powered by Linux