Thanks Nikha but its already dere :
<html>
<head>
<script>
function week_report_fun(){
var ajaxRequest; // The variable that makes Ajax possible!
try{
// Opera 8.0+, Firefox, Safari
ajaxRequest = new XMLHttpRequest();
}catch (e){
// Internet Explorer Browsers
try{
ajaxRequest = new ActiveXObject("Msxml2.XMLHTTP");
}catch (e) {
try{
ajaxRequest = new ActiveXObject("Microsoft.XMLHTTP");
}catch (e){
// Something went wrong
alert("Your browser broke!");
return false;
}
}
}
ajaxRequest.onreadystatechange = function(){
if(ajaxRequest.readyState == 4){
var ajaxDisplay = document.getElementById('ajaxDiv');
ajaxDisplay.innerHTML = ajaxRequest.responseText;
}
}
var users = document.getElementById('users').value;
var queryString = "?users=" + users ;
//document.write(queryString);
ajaxRequest.open("GET","ajaxex.php?q="+users,true);
ajaxRequest.send();
}
</script>
</head>
<body>
<form>
User : <select id="users">
<option value="">Select a user</option>
<option value="133">a.v</option>
<option value="168">ad</option>
</select>
<input type='button' onclick="week_report_fun()"
value='Weekly Report'/>
</form>
<br>
</body>
</html>
Sorry My bad , i didn't mention the complete program in my first mail
Thanks
On Thu, Jan 30, 2014 at 2:36 PM, Domain nikha.org <mail@xxxxxxxxx> wrote:
> Adarsh Sharma am Donnerstag, 30. Januar 2014 - 07:27:
>
> > Hi,
> >
> > I am using AJAX and php for creating a small UI that retrieves data from
> > mysql upon clicking on one button. But i clicked on that , nothing is
> > happening. Below is my index.html :
> >
> > *-- index.html *
> >
> > <html>
> > <head>
> > function week_report_fun(){
> > var ajaxRequest;
> > ---
> > ---
> > --
> > ajaxRequest.open("GET","ajaxex.php?q="+users,true);
> > ajaxRequest.send();
> > }
> >
> > </script></head><body>
> > <form>
> > User : <select id="users" onchange="week_report_fun()">
> > <option value="">Select a user</option>
> > <option value="133">av</option>
> > <option value="168">ad</option>
> > <option value="78">so</option>
> > <option value="239">ak</option>
> > </select></form><br>
> > <div id="txtHint"><b>Person info will be listed here.</b></div>
> > </body></html>
> >
> > *Access Log Output :-*
> >
> > 1.4.15.25 - - [30/Jan/2014:06:05:52 +0000] "GET /project/ajaxex.php?q=133
> > HTTP/1.1" 200 5323 "http://db11.app.com/project/"; "Mozilla/5.0
> (Macintosh;
> > Intel Mac OS X 10_9_1) AppleWebKit/537.36 (KHTML, like Gecko)
> > Chrome/32.0.1700.102 Safari/537.36"
> > 1.4.15.25 - - [30/Jan/2014:06:06:13 +0000] "GET
> /project/ajaxex.php?q=133
> > HTTP/1.1" 200 5323 "-" "Mozilla/5.0 (Macintosh; Intel Mac OS X 10_9_1)
> > AppleWebKit/537.36 (KHTML, like Gecko) Chrome/32.0.1700.102
> Safari/537.36"
> >
> > No errors in error.log.
> >
> > Strange thing if i directly open below link in the browser, report is
> > coming and i am able to see in the browser :
> >
> > *http:///db11.app.com/project/ajaxex.php?q=133
> > <http://db11.app.com/project/ajaxex.php?q=133>*
> >
> > It means my ajaxex.php is fine and no issues but dont understand why it
> is
> > not working as expected after clicking on button.Please let me know if i
> am
> > missing something.
> >
> >
> > Thanks
> >
> Hi Adarsh!
> Yes, you are missing something: The opening <script> tag in your html head!
> without that, your ajax code is simply ignored.
>
> Hope it helps
> Niklaus
>
