On Mar 15, 2013 9:54 PM, "Sebastian Krebs" <krebs.seb@xxxxxxxxx> wrote: > > 2013/3/16 Andrew Ballard <aballard@xxxxxxxxx> >> >> I suppose one could try something like this: >> >> if (is_string($val) && $val === (string)(int)$val) .... >> >> If $val is an integer masquerading as a string, it should be identical to >> the original string when cast back to a string, shouldn't it? (I can't try >> it right now.) > > > It is semantically equivalent to > > $val == (int) $val > > and as far as I remember (I didn't read everything completely) this were mentioned. I didn't read, whether or not, it was accepted as solution ;) > Not quite. That method will massage both values to the same type for the comparison. Whoever shot it down said they both go to int. If that's the case, if ($val == (int)$val) is more like saying if ((int)$val === (int)$val) What I suggested converts the string to an int, the resulting int back to a string, then does a type-specific comparison to the original string value. Andrew
