On Thu, 15 Mar 2012 12:09:53 -0500, Jay Blanchard
<jay.blanchard@xxxxxxxxxxxxxxxxxxx> sent:
I thought that fgetcsv returned an array. I can work with it like an
array but I get the following warning when using it
|Warning: implode(): Invalid arguments passed on line 155
154 $csvCurrentLine = fgetcsv($csvFile, 4096, ',');
155 $currentLine = implode(",", $csvCurrentLine);
|
Everything that I have read online indicates that it is because
$csvCurrentLine is not declared as an array. Adding a line to the code
153 |$csvCurrentLine = array();
Does not get rid of the warning. The warning isn't interfering with the
script working, but it us annoying. Does anyone know the solution?
Thanks!
Jay
|
Just want to clarify something not directly related to the OP's question:
This:
153 |$csvCurrentLine = array();
Does not set a *type* for $csvCurrentLine, so if you're next line is this:
154 $csvCurrentLine = fgetcsv($csvFile, 4096, ',');
Any previous assignments are lost; the notion that presetting
$csvCurrentLine to an array has no bearing when you then immediately
set the same variable to something else.
The "type" $csvCurrentLine has after line 154 is entirely dependent on
what fgetcsv() is returning, and nothing that happened prior to line
154.
--
Tamara Temple
aka tamouse__
May you never see a stranger's face in the mirror
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