On 3/15/2012 12:23 PM, Matijn Woudt wrote:
On Thu, Mar 15, 2012 at 6:09 PM, Jay Blanchard <jay.blanchard@xxxxxxxxxxxxxxxxxxx> wrote:I thought that fgetcsv returned an array. I can work with it like an array but I get the following warning when using it |Warning: implode(): Invalid arguments passed on line 155 154 $csvCurrentLine = fgetcsv($csvFile, 4096, ','); 155 $currentLine = implode(",", $csvCurrentLine); | Everything that I have read online indicates that it is because $csvCurrentLine is not declared as an array. Adding a line to the code 153 |$csvCurrentLine = array(); Does not get rid of the warning. The warning isn't interfering with the script working, but it us annoying. Does anyone know the solution? Thanks! Jay |Are you using this in a loop or something? fgetcsv returns FALSE on errors, including End Of File. [/snip]
I am using it in a loop. End Of File is an error? -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
