On Fri, Mar 9, 2012 at 9:23 AM, Tedd Sperling <tedd.sperling@xxxxxxxxx> wrote:
> On Mar 8, 2012, at 6:53 PM, Daniel Brown wrote:
> On Mar 8, 2012 6:14 PM, "Tedd Sperling" <tedd.sperling@xxxxxxxxx> wrote:
>>
>> > Side-point: I find it interesting that getdate() has all sorts of neat descriptions for the current month (such as, what weekday a numbered day is), but lacks how many days are in the month. Doesn't that seem odd?
>>
>> Oh, I see what you're saying now. Well, using getdate(), how else would you think to pass the parameter to get the last day other than using the current month and the last day (which would then obviously be overkill, of course).
>
> Well.. you could use any number that exceeds 31 -- or -- as I would have suggested if it had been up to me, zero day would provide the number of days in *that* month rather than the number of days in the previous month, which was the point of my post.
>
>> All of this aside, though, you may instead want to use something along the lines of date('d',strtotime('last day of this month')); in tandem with your date formatting.
>
> That's a good idea, but
>
>> date('d',strtotime('last day of this month'));
>
>
> gives me the number of days in *this* month, but not the next, or previous, month.
>
> I need the result to be whatever date was selected -- something like:
>
> $number_days = date('d',strtotime('last day of April, 2014'));
>
> But that doesn't work.
>
> You see, I need something that makes sense to students. The idea that you have to use the zero day (whatever that is) of the next month to see how many days there are in this month is strange and confusing -- again my point.
>
> Thus far, the following looks better than what I came up with::
>
> $what_date = getdate(mktime(0, 0, 0, $mon, 32, $year));
> $days_in_month = 32 - $what_date['mday'];
>
> But it's still strange.
>
> I was using:
>
> // get the last day of the month
> $cont = true;
> $tday = 27;
> while (($tday <= 32) && ($cont))
> {
> $tdate = getdate(mktime(0,0,0,$mon,$tday,$year));
> if ($tdate["mon"] != $mon)
> {
> $lastday = $tday - 1;
> $cont = false;
> }
> $tday++;
> }
>
> It made sense, but was too long. I figured there should be something better and easier to explain -- but I'm still looking.
function count_days($month, $year) { return (mktime(0, 0, 0, $month+1,
1, $year) - mktime(0, 0, 0, $month, 1, $year))/86400; }
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
