Hi, All
To bring a work-around into this discussion I myself would not see it
as a good way to do it like that - even if the documentation provides
some information around that.
Here's what I have done in all new projects I worked with time-calculation:
@Tedd: Lets pick up your first example and work with the
DateTime-Object instead:
$date = new DateTime($year . '-' . $current_month . '-1');
$date->add( new DateInterval( 'P1M' ) ); // Add a period of 1 month to
the date-instance (haven't tried that with the 30th of Jan ... would
be kind-of interesting)
$days_in_current_month = $date->format('j'); // Get the date of the month
As this does not solve the problem (as we still should update the
documentation or the code if it does not match) it's not a solution,
but a suggestion to coding-style at all.
It seems a bit cleaner to me as you don't have to worry about the 13th
month, time-zones or other things that can be difficult to calculate
yourself.
Bye
Simon
2012/3/8 shiplu <shiplu.net@xxxxxxxxx>:
>> To get the number of days for a specific month, I use:
>>
>> // $current_month is the month under question
>>
>> $next_month = $current_month + 1;
>
> I use this
>
> $next_month = $current_month + 1;
> $next_month_1 = mktime(0, 0, 0, $next_month, 1, date("Y") );
> $current_month_1= mktime(0, 0, 0, $current_month, 1, date("Y") );
> $mdays = ($current_month_1 - $next_month_1)/(3600*24);
>
> It's much more easier if you use DateTime and DateInterval class
>
>
>
> --
> Shiplu.Mokadd.im
> ImgSign.com | A dynamic signature machine
> Innovation distinguishes between follower and leader
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
