On 4 Mar 2012, at 14:31, Ruwan Pathmalal wrote: > I confused with weird behaviour of array. Following is my script. > > <?php > $array = array( > '12_1'=>array( > 56=>array( > 23=>'23', > 33=>'33') > ), > '12_5'=>array( > 55=>'55' > ) > ); > > $array['12_5'][55][45] = '45'; > $array['12_5'][55][56] = '76'; > $array['12_5'][55][85] = '85'; > $array['12_5'][55][96] = '96'; > print_r($array); > ?> > > Output is -: > Array ( [12_1] => Array ( [56] => Array ( [23] => 23 [33] => 33 ) ) [12_5] > => Array ( [55] => 55 4 7 8 9 ) ) > > Sometime this is because, first time $array['12_5'][55] not an array. I > assigned value to it like array. (I suppose overwrite key and then assign > given value as key value pair). See this part of output [12_5] => Array ( > [55] => 55 4 7 8 9 ). It compose 4 from 45, 7 from 76, 8 from 85 like that > (first digit of assigned values). > > I manage to overcome this problem by unsettling $array['12_5'][55] before > assigning value to it. > > But I want to know why this happening or is this PHP bug ? (Clear > explanation for situation :) ) Not a bug. You set $array['12_5'][55] to a string, then you try to use it as an array. Strings can be accessed as arrays. > $array['12_5'][55][45] = '45'; This line sets the 45th character in the string to 4 (each element of a string accessed as an array can only contain a single character, so it throws the 5 away). > $array['12_5'][55][56] = '76'; > $array['12_5'][55][85] = '85'; > $array['12_5'][55][96] = '96'; Likewise with these. You're not seeing the additional spaces because you're viewing it as an HTML page. Run it on the command line or add <pre> before the <?php to see the actual value, which is... "55 4 7 8 9" -Stuart -- Stuart Dallas 3ft9 Ltd http://3ft9.com/ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
