Re: how to execute Exe file in system

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On Fri, Feb 17, 2012 at 2:19 PM, Stuart Dallas <stuart@xxxxxxxx> wrote:

> On 17 Feb 2012, at 12:12, Negin Nickparsa wrote:
> > if (($out = system(' "C:/Program Files/GAMS23.7/gams.exe "C:/Program
> > Files/GAMS23.7/trnsport_php.gms')) !== FALSE)
> > {
> > print('Not error!');
> > printf('Output is "%s"', $out);
> > }
> > else
> > {
> > print('Error');
> > }
> > Fatih it shows again nothing why I should set the full path even when I
> run
> > my file on the path I don't think so that it is needed I don't know how
> to
> > work with these quotations was it right Duken?
>
>
> * Use back ticks to get the full output.
> * Use escapeshellcmd and escapeshellarg to ensure the command is built in
> a safe and valid way.
> * Redirect stderr to stdout using 2>&1 so you see any error messages that
> are being generated.
>
> $cmd = escapeshellcmd('C:/Program Files/GAMS23.7/gams.exe').'
> '.escapeshellarg('C:/Program
> Files/GAMS23.7/trnsport_php.gms').' 2>&1';
> $out = `$cmd`;
> var_dump($out);
>
> Try that, then you can build logic that checks the output for errors. You
> may also want to make sure that safe_mode is disabled, though I doubt
> that's the problem.
>
> -Stuart
>
> --
> Stuart Dallas
> 3ft9 Ltd
> http://3ft9.com/


it is espacing issue as Stuart stated.. try this one thats working for me
with spaces

//$out = shell_exec("\"C:/Program Files/tws_date.exe\""); tws_date is c
program prints date. nothing special
$out = shell_exec("\"C:/Program Files/GAMS23.7/gams.exe\" \"C:/Program
Files/GAMS23.7/trnsport_php.gms\"");

if ($out) {
    echo "OK: " . $out;
} else {
    echo "ERROR";
}

var_dump($out);

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