On 12 Feb 2012, at 18:51, Tim Streater wrote:
> I have a function defined thus:
>
> function my_func (&$arg1, $arg2, $arg3, $arg4, $arg5, &$arg6)
> {
>
> // code here
>
> }
>
> I call this with variously the first three arguments only, or all six, taking care that if I call it with fewer arguments then I don't try to acces $arg4, $arg5, or $arg6 (which is passed by reference, as is $arg1).
>
> On my first attempt to execute this, I'm getting:
>
> Missing argument 4 for my_func(), called in /path/to/source/file1.php at line 556 and defined
> in /path/to/source/file2.php at line 3
>
> Is this because $arg6 is passed by reference? There is some reference to this in the docs and the user notes but it's a little unclear. Or is there another reason?
Optional arguments must be given a default value...
function my_func(&$arg1, $arg2, $arg3, $arg4 = null, $arg5 = null, &$arg6 = null)
Note that passing a default value by reference was not supported prior to PHP5.
All the relevant details are here: http://php.net/functions.arguments
-Stuart
--
Stuart Dallas
3ft9 Ltd
http://3ft9.com/
--
PHP General Mailing List (http://www.php.net/)
To unsubscribe, visit: http://www.php.net/unsub.php
