> -----Original Message----- > From: Gates, Jeff [mailto:GatesJ@xxxxxx] > Sent: Wednesday, August 03, 2011 10:23 AM > To: php-general@xxxxxxxxxxxxx > Subject: Syntax Question > > I, too, am a super newbie. I have a beginning knowledge of being able > to > "read" php and understand its syntax but I can¹t write it. This is a > bit > complicated but here¹s my problem: > > I want to create a variable in PHP that I can use to link to an image > in our > museum's image website. We have done it with ColdFusion here but I need > the > same thing for PHP because I¹m building a site using a php-based CMS > called > Omeka. > > In ColdFusion the variable is written: > <cfset tmpImageDirectory = getToken(artwork.accessionNumber, 1, ".")> > > Basically, it¹s saying find the image on our server by looking for its > accession number within the year directory. Since the first part of the > accession number is the year we got the artwork this variable is saying > look > for the accession number in the year directory by first looking at the > first > part of that accession number (the year), look in that year directory > and > then use the entire accession number to find the image within that > directory. An example of an accession number is 2011.15. That¹s saying > that > artwork was the 15th artwork brought into our collection in 2011. On > our > image server it will be found in a directory called 2011. (Am I making > sense?) > > Then the Coldfusion call is: > > <a > href="http://ids.si.edu/ids/dynamic?container.fullpage&id=http://americ > anart > .si.edu/images/#tmpImageDirectory#/#artwork.accessionNumber#_1a.jpg"> > (the > 1a.jpg is simply the size image we want to call). > > I need to be able to do the same thing with PHP but have no idea how. > > More information: within my site I¹m housing the accession number in a > mySQL > database. I¹ve gotten a bit of help on this already (but not enough, > that¹s > why I¹m turning to you). > > I was told I need to create two variables [('Dublin Core','Identifier') > is > the name of the field that houses the accession number): > > $accessionNumber = item('Dublin Core','Identifier'); > $tmpImageDirectory = strtok($accessionNumber,"."); > > And then create a third variable to create a url variable > > $url = > "http://ids.si.edu/ids/dynamic?container.fullpage&id=http://americanart > .si.e > du/images/ > <http://ids.si.edu/ids/dynamic?container.fullpage&id=http://americanart > .si.e > du/images/$tmpImageDirectory/$artwork.accessionNumber_1a.jpg> " + > $tmpImageDirectory + "/" + $accessionNumber + "_1ajpg"; > > That's as far as I've gotten. I don't know how to put all of these > together > using proper PHP syntax. Can someone help me with this? Thanks. > > Best, Jeff > > > > -- > PHP General Mailing List (http://www.php.net/) > To unsubscribe, visit: http://www.php.net/unsub.php $url = "http://ids.si.edu/ids/dynamic?container.fullpage&id=http://americanart.si.e du/images/ <http://ids.si.edu/ids/dynamic?container.fullpage&id=http://americanart.si.e du/images/". $tmpImageDirectory ."/". $artwork ."accessionNumber_1a.jpg> ". $tmpImageDirectory ."/". $accessionNumber ."_1ajpg"; I am not sure I agree with the way you are setting the $url it looks like you have mashed and a url hyperlink partially into 1. Like you are trying to set the $url as a image with a link are you trying to set a link or an image as the $url? If you are trying to set a image as the $url do this. $url = "<image src=http://ids.si.edu/ids/dynamic?container.fullpage&id=http://americanart.s i.edu/images/". $tmpImageDirectory ."/". $accessionNumber ."_1ajpg ALT=''>"; Sorry if this is not correct for what you are trying to do. I just do not understand the intent. -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
