Re: newbie date time question

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On 23/06/11 12:30 AM, Richard Quadling wrote:
On 22 June 2011 15:05, David Nicholls<dcn@xxxxxxxxxxxxxx>  wrote:
I'm trying to convert a date and time string using strtotime()

The date and time strings are the first entry in each line in a csv file in
the form:

22/06/2011 9:47:20 PM, data1, data2,...

I've been trying to use the following approach, without success:

function read_data($filename)
{
    $f = fopen($filename, 'r');
    while ($d = fgetcsv($f)) {

        $format = 'd/m/Y h:i:s';
        $dt = DateTime::createFromFormat($format, $d[0]);

        $data[] = array(strtotime($dt), $d[1]); //convert date/time
    }
    fclose($f);
    return $data;
}

Obviously I'm not getting the $format line right, as the resulting $dt
values are empty.  (I have previously used this reading process successfully
with better behaved date and time strings).

Advice appreciated.

DN

<?php
$data = '22/06/2011 9:47:20 PM';
$format = 'd/m/Y g:i:s A';
$datetime = DateTime::createFromFormat($format, $data);
echo date('r', $datetime->getTimestamp());
?>

outputs ...

Wed, 22 Jun 2011 21:47:20 +0100

Yes, partly works, but I'm now getting:

Wed, 22 Jun 2011 20:19:56 +1000
Warning: strtotime() expects parameter 1 to be string, object given in <xxx>.php on line 12

in:

5  function read_data($filename)
6  {
7      $f = fopen($filename, 'r');
8      while ($d = fgetcsv($f)) {
9       	$format = 'd/m/Y g:i:s A';
10      	$dt = DateTime::createFromFormat($format, $d[0]);
11		echo date('r', $dt->getTimestamp());

12        $data[] = array(strtotime($dt), $d[1]); //convert date/time

13    }
14    fclose($f);
15    return $data;
15    }

So $dt is apparently not a string?

DN

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