On 20 May 2011 16:22, Geoff Lane <geoff@xxxxxxxxxxxxx> wrote:
> ÂOn Friday, May 20, 2011, JoÃo CÃndido de Souza Neto wrote:
>
>> What about using this:
>
>> $date = DateTime::createFromFormat("Y-m-d", "2011-05-20");
>
> Hi JoÃo, and thanks for your help.
>
> FWIW, I thought about that but it didn't work for me. On further
> investigation, I'm now completely confused and suspect I've got a duff
> PHP installation. Thankfully, it's a virtual machine so it should be
> reasonable easy to 'vapourise' and start over (perhaps with CentOS
> rather than Ubuntu as the OS).
>
> Anyway, the following code produces the following result when the
> variable $str = '7 feb 2010':
>
> [code]
> Âecho "<p>Date is $str</p>\n";
> Â$date = DateTime::createFromFormat('d M Y', $str);
> Âecho "<pre>";
> Âprint_r($date);
> Âecho "</pre>\n";
> Âecho date('d M Y') . "<br />" . date('d M Y', $date);
> [/code]
>
> [result]
> Â<p>Date is 7 feb 2010</p>
> Â<pre>DateTime Object
> Â(
> Â Â Â[date] => 2010-02-07 15:11:34
> Â Â Â[timezone_type] => 3
> Â Â Â[timezone] => Europe/London
> Â)
> Â</pre>
> Â20 May 2011<br />
> [/result]
>
> This is pretty much as expected except that the second call to date()
> - i.e. date('d M Y', $date) - outputs nothing.
date() takes an int as second parameter - a timestamp. Not an object.
And from a quick test it doesn't look like DateTime has a __toString
method.
> Also, AFAICT createFromFormat fails if the date is not formatted
> according to the first parameter. So, for example:
> Â$date = DateTime::createFromFormat('d M Y', '5/2/10')
> fails ... (at least, it does on my system :( )
>
I'm sorry for asking but what did you expect?? You're specifically
calling a method that parses a string according to a given format. If
it parsed the string according to any other format, that would be a
huge WTF.
Regards
Peter
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