Re: 95th percentile of an array.

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On Sun, Jan 30, 2011 at 10:39 PM, Adam Richardson <simpleshot@xxxxxxxxx>wrote:

> On Sun, Jan 30, 2011 at 8:44 PM, Marc Trudel <mtrudel@xxxxxxxxxx> wrote:
>
>> Just out of curiosity, wouldnt it be better to use floor($n) instead of
>> round($n-0.5)?
>>
>
> Hi Marc,
>
> I don't think so, although I could have missed something (I just quick
> cranked out the example.)  The definition I linked to involves rounding (2.5
> would round to 3, and 2.4 would round to 2), so I just included the rounding
> in the equation.  Let me know if you see something I botched.
>
> Thanks,
>
> Adam
>
> --
> Nephtali:  A simple, flexible, fast, and security-focused PHP framework
> http://nephtaliproject.com
>

Hi again Marc,

One other note.  Maybe you were suggesting that the equation should have
been reduced to floor($n) instead round($n - .5).

I purposely tried to stay true to the equation/algorithm provided in the
link so it would be easy for the OP to see exactly where I got the equation
from and how I mapped it to PHP code (although I did have to adjust the
equation for zero indexes used in arrays.)

That all said, if you wanted to reduce the equation to floor($n) to produce
a more succinct representation, then you could certainly make that change
and it would produce the same result.

Thanks,

Adam

-- 
Nephtali:  A simple, flexible, fast, and security-focused PHP framework
http://nephtaliproject.com

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