At 1:50 PM -0400 9/24/10, Andy McKenzie wrote:
Hey folks,
Here's the deal. I have the following code:
if($col_vals[$i][$val['column']] == $search_result[0][$col])
{ echo ' selected="selected"'; }
elseif($val['default'] == $col_vals[$i][$val['column']])
{ echo ' selected="selected"'; }
It's supposed to check whether there's a value in the db
($search_result[0][$col]) that matches the current column value, and
if not, check whether the default matches it. It does that, sort of.
In fact, both statements trigger, which I would have said wasn't
possible.
So the question is: what causes both parts of an if/elseif
statement to trigger? As far as I can see my punctuation is correct,
and I've confirmed through debugging statements that all the values
are what I expect, so how do I make the elseif stop acting like
another if? Or, alternatively, have I just misunderstood all this
time what the if/elseif statement does?
Thanks,
Alex
Alex:
I am not in the majority when I say for conditions where you have
more than two options use a switch control and not an elseif.
In 40+ years of programming, I have never used elseif because the
control confuses me. It is *much* easier for me to use, understand,
and document a switch statement than an elseif.
Your mileage may vary.
Cheers,
tedd
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