hello list, I'm trying to manage a image resouce inside a method, but unsuccessfully... In detail, that's some code snippets: the class and the method: class.php class canvas{ function makeImage($imageWidth = 850){ $im = imagecreate(110, 20) or die("Cannot Initialize new GD image stream"); $background_color = imagecolorallocate($im, 0, 0, 0); $text_color = imagecolorallocate($im, 233, 14, 91); imagestring($im, 1, 5, 5, "A Simple Text String", $text_color); return $im; } } ... than my test.php file: header("Content-type: image/png"); include_once("class.php"); $c = new canvas(); imagepng($c->makeImage()); the result in the browser isn't the image itself, but an error that sounds like: (I traslate the message from italian): "Image can't be displayed because contains some errors" but... if I comment out the "header" line, I get this: ‰PNG ��� IHDR���n������V,š���PLTE���é[an÷���fIDAT•c` `fxÄÀÃ`Ç ÀçÀä²41ƒ‚€˜Ë–Ý’Àq²@੤;{á0— œi ...sounds like a png image, isn't it? but It doesn't :-/ The code in the method is very simple, is the same of the php manual page of "imagecreate" function, and I think the resource is correctly managed, 'cause if I write this: $c = new palinsestoCanvas(3); imagepng(null); I get: "Warning: imagepng(): supplied argument is not a valid Image resource" .. so I think $c->makeImage()) returns successfully the resource.. but I still didnt see my image.. Any help is appreciated, thanks Lorenzo