Re: regular expression

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On 2 June 2010 16:35, Jan G.B. <ro0ot.w00t@xxxxxxxxxxxxxx> wrote:
> 2010/6/1 Peter Lind <peter.e.lind@xxxxxxxxx>:
>> On 1 June 2010 17:33, Ashley Sheridan <ash@xxxxxxxxxxxxxxxxxxxx> wrote:
>>> On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote:
>>>
>>>> $re1 = '/^[a-z]++$/i';
>>>> $re2 = '/^[a-z ]++$/i';
>>>>
>>>>
>>>>
>>>> --
>>>> -----
>>>> Richard Quadling
>>>> "Standing on the shoulders of some very clever giants!"
>>>> EE : http://www.experts-exchange.com/M_248814.html
>>>> EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
>>>> Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731
>>>> ZOPA : http://uk.zopa.com/member/RQuadling
>>>>
>>>
>>>
>>> Why the double ++ in the expressions there? Surely one + would match the
>>> 1 or more characters that you need and the second one would just be
>>> surplus?
>>>
>>
>> Equally important: why have three people already done this persons
>> homework. 5 minutes googling would have answered this ...
>>
>
> Even more important: No answer is correct, because f.e. "äüßćéâ" are
> also letters.
>
> Bye
>
> ;-)
>

So, would ...

/^[^\p{M}\p{Z}\p{N}\p{P}\p{S}\p{C}\d\s]++$/i

be ok?



-- 
-----
Richard Quadling
"Standing on the shoulders of some very clever giants!"
EE : http://www.experts-exchange.com/M_248814.html
EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731
ZOPA : http://uk.zopa.com/member/RQuadling

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