Re: regular expression

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2010/6/1 Peter Lind <peter.e.lind@xxxxxxxxx>:
> On 1 June 2010 17:33, Ashley Sheridan <ash@xxxxxxxxxxxxxxxxxxxx> wrote:
>> On Tue, 2010-06-01 at 16:31 +0100, Richard Quadling wrote:
>>
>>> $re1 = '/^[a-z]++$/i';
>>> $re2 = '/^[a-z ]++$/i';
>>>
>>>
>>>
>>> --
>>> -----
>>> Richard Quadling
>>> "Standing on the shoulders of some very clever giants!"
>>> EE : http://www.experts-exchange.com/M_248814.html
>>> EE4Free : http://www.experts-exchange.com/becomeAnExpert.jsp
>>> Zend Certified Engineer : http://zend.com/zce.php?c=ZEND002498&r=213474731
>>> ZOPA : http://uk.zopa.com/member/RQuadling
>>>
>>
>>
>> Why the double ++ in the expressions there? Surely one + would match the
>> 1 or more characters that you need and the second one would just be
>> surplus?
>>
>
> Equally important: why have three people already done this persons
> homework. 5 minutes googling would have answered this ...
>

Even more important: No answer is correct, because f.e. "äüßćéâ" are
also letters.

Bye

;-)

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