Re: No notices for undefined index

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Bob McConnell wrote:
> In the first case, $a=5 creates a multi-typed variable. The interpreter
> makes its best guess how the next two expressions should be interpreted.
> In both cases, they look a lot like an index into a character array
> (string), and 'test' evaluates numerically to zero. Both are valid
> offsets for a string, so no messages are generated.
> 
> In the second case, $a is explicitly declared as an array. This give the
> interpreter a lot more detail to work from. The two expressions are now
> an index and a key for the array. But both of them evaluate to offsets
> that have not been assigned, which raises a flag and creates the
> warnings.
> 
> Such are the joys of loosely typed languages.
> 
> Bob McConnell

Yes, this is what I was thinking as well, however:

$a=5;
print $a[0];   // if it is index 0 then it should print 5 yes?
print $a[100]; // there is no index 100 so why no notice?

-- 
Thanks!
-Shawn
http://www.spidean.com

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