Hello Shawn, Hm... isn't it expected behavior? Since you haven't defined a $a['test'] item, PHP throws a notice... or I'm wrong? -- With best regards from Ukraine, Andre Skype: Francophile; Wlm&MSN: arthaelon @ yandex.ru; Jabber: arthaelon @ jabber.org Yahoo! messenger: andre.polykanine; ICQ: 191749952 Twitter: m_elensule ----- Original message ----- From: Shawn McKenzie <nospam@xxxxxxxxxxxxx> To: php-general@xxxxxxxxxxxxx <php-general@xxxxxxxxxxxxx> Date: Thursday, April 8, 2010, 8:36:21 PM Subject: No notices for undefined index So the first two print statements generate NO notices, while the second obviously generates: Notice: Undefined offset: 1 in /home/shawn/www/test.php on line 11 Notice: Undefined index: test in /home/shawn/www/test.php on line 12 This sucks. A bug??? error_reporting(E_ALL); ini_set('display_errors', '1'); $a = 5; print $a[1]; print $a['test']; $a = array(); print $a[1]; print $a['test']; -- Thanks! -Shawn http://www.spidean.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php