On Wed, Aug 12, 2009 at 10:25 AM, Robert Cummings <robert@xxxxxxxxxxxxx>wrote:
>
>
> tedd wrote:
>
>> At 4:08 PM -0400 8/11/09, Robert Cummings wrote:
>>
>>> tedd wrote:
>>>
>>>> Hi gang:
>>>>
>>>> I want to show the dates for all Fridays +-30 days from a specific date.
>>>>
>>>> For example, given today's date (8/11/2009) the Fridays that fall +-30
>>>> days are July 17, July 24, July 31, Aug 7, Aug 14, Aug 21, Aug 28, and Sept
>>>> 4.
>>>>
>>>> I'm curious, how would you guys solve this?
>>>>
>>> <?php
>>>
>>> $fridays = array();
>>> for( $i = -30; $i <= 30; $i++ )
>>> {
>>> $mod = $i < 0 ? $i : '+'.$i;
>>>
>>> $time = strtotime( $mod.' day' );
>>>
>>> if( date( 'D', $time ) == 'Fri' )
>>> {
>>> $fridays[] = date( 'Y-m-d', $time );
>>> }
>>> }
>>>
>>> print_r( $fridays );
>>>
>>> ?>
>>>
>>> Cheers,
>>> Rob.
>>>
>>
>> Rob:
>>
>> That's slick -- you never let me down with your simplicity and creativity.
>>
>> My solution was to find the next Friday and then cycle through +-28 days
>> (four weeks) from that date, like so:
>>
>> <?php
>> $fridays = array();
>>
>> for( $i = 1; $i <= 7; $i++ )
>> {
>> $time = strtotime( $i . ' day' );
>> if( date( 'D', $time ) == 'Fri' )
>> {
>> $start = 28 - $i;
>> $end = 28 + $i;
>> }
>> }
>>
>> for( $i = -$start; $i <= $end; $i += 7 )
>> {
>> $time = strtotime( $i . ' day' );
>> $fridays[] = date( 'Y-m-d', $time );
>> }
>>
>> print_r( $fridays );
>> ?>
>>
>> Your solution had 61 iterations (for loop) while mind had only 21, so
>> mine's a bit faster. Here's the comparison:
>>
>> http://php1.net/b/fridays/
>>
>> But I'll use your solution -- it's more elegant.
>>
>> Thanks for the code,
>>
>> tedd
>>
>
> I think Shawn McKenzie's is the best. It seems his would take at most 12
> iterations.
>
> Cheers,
> Rob.
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>
Hi all
This is my point of view.
I try to stay the most legible and simple as possible.
@tedd: can you benchmark this script too? usualy legibility > performance
<?php
$fridays = array(); # I'll store the friday here
$day = strtotime('-1 month', time() ); # let's start at one month ago
while( 5 != date('w', $day)) # advance to a friday
$day = strtotime('+1 day', $day);
# I'll stop when $day where ahead one month from today
$end = strtotime( '+1 month', time() );
do{
$friday[] = date('Y-m-d', $day); # store the friday
$day = strtotime('+1 week', $day); # advance one week
} while( $day < $end );
# job's done!
print_r( $friday );
--
Martin Scotta
