Re: Call to object function, want to PHP interpret returned string

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John Allsopp wrote:

> Hi
> 
> At the top of a webpage I have:
> 
> <?php
> include_once("furniture.php");
> $myFurniture = new furniture();
> echo $myFurniture->getTop("my company title");
> ?>
> 
> to deliver the first lines of HTML, everything in HEAD and the first
> bits of page furniture (menu, etc).
> 
> In the furniture object in getTop(), I want to return a string that
> includes the CSS file that I call with an include_once. But the
> include_once isn't interpreted by PHP, it's just outputted. So from:
> 
>         $toReturn = "<!DOCTYPE html PUBLIC '-//W3C//DTD XHTML 1.0
> Transitional//EN' ........
>             <?php
>                 include_once('styles3.txt');
>             ?>
>             .......";
> 
>         return $toReturn;
> 
> I get
> 
> <?php
> include_once('styles3.txt');
> ?>
> 
> in my code.
> 
> Do I really have to break up my echo $myFurniture->getTop("my company
> title"); call to getTopTop, then include my CSS, then call getTopBottom,
> or can I get PHP to interpret that text that came back?
> 
> PS. I may be stupid, this may be obvious .. I don't program PHP every day
> 
> Thanks in advance for your help :-)
> 
> Cheers
> J

First guess is that your page doing the including doesn't have a filename
with a .php extension, and your server is set to only parse php in files
with a .php extension.



Cheers
-- 
David Robley

If you saw a heat wave, would you wave back?
Today is Boomtime, the 41st day of Confusion in the YOLD 3175. 


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