Re: Compare and inserting with php

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>>
>
> Does this list of inspections exist in the db? Could you not use an
> INSERT INTO SELECT * FROM TABLE WHERE type statement...much less
> processing overhead then
>
> --
>
> Bastien
>
> Cat, the other other white meat
>
> Hi Bastien,
>
> Something like this is what you mean?
>
>  if (!empty($Go)) {    $query = "SELECT * FROM restaurants WHERE name = '$ucName' AND address = '$ucAddress' AND inDate ='$inDate' AND inType = '$inType' ";    $result = mysql_query ($query);    $row = mysql_fetch_object ($result);    If (mysql_num_rows($result) == 0) { $sql = "INSERT INTO `restaurants` (name, address, inDate, inType, notes, critical, cviolations, noncritical)  VALUES (";    $sql .= " '$ucName', '$ucAddress', '$inDate', '$inType', '$notes', '$critical', '$cleanViolations', '$noncritical')";        $result = mysql_query($sql) or die(mysql_error());    }        So if all three things are met, that entry is in there if not insert right?
>

More like

sql = "insert into restaurants select * from restaurants where name =
'$ucName' AND address = '$ucAddress' AND inDate ='$inDate' AND inType
= '$inType' ";

http://dev.mysql.com/doc/refman/5.0/en/insert-select.html



--

Bastien

Cat, the other other white meat


Well I didn't get anywhere, now I just keep getting this error....


Warning: mysql_num_rows(): supplied argument is not a valid MySQL result resource in /var/www/vhosts/getpublished.news-leader.com/httpdocs/ResturantInspections/compare.php on line 119
You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 's Roast Beef Restaurant #9459', ' 1833 W Republic Rd ', '3/2/09', '' at line 1

Using this code:

 $query = "SELECT * FROM  restaurants  WHERE  name = '$ucName' AND address = '$ucAddress' AND inDate ='$inDate' AND inType = '$inType' ";    $result = mysql_query ($query);   // $row = mysql_fetch_object ($result);        echo $result;    If (mysql_num_rows($result) == 0) {    $sql = "INSERT INTO `restaurants` (name, address, inDate, inType, notes, critical, cviolations, noncritical)  VALUES (";    $sql .= " '$ucName', '$ucAddress', '$inDate', '$inType', '$notes', '$critical', '$cleanViolations', '$noncritical')";        $result = mysql_query($sql) or die(mysql_error());    }

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