Re: Re: reference variables

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On Fri, 2009-05-22 at 07:44 -0500, Shawn McKenzie wrote:
> kranthi wrote:
> > i have this script
> > 
> > <?php
> > $x = 1;
> > $y = 2;
> > $a1 = array(&$x, &$y);
> > $a2 = array($x, $y);
> > $a2[0] = 3;
> > print_r($a1);
> > print_r($a2);
> > ?>
> > 
> > i am expecting
> > 
> > Array
> > (
> >     [0] => 3
> >     [1] => 2
> > )
> > Array
> > (
> >     [0] => 3
> >     [1] => 2
> > )
> > 
> > 
> > while i m getting
> > 
> > Array
> > (
> >     [0] => 1
> >     [1] => 2
> > )
> > Array
> > (
> >     [0] => 3
> >     [1] => 2
> > )
> > 
> > 
> > any ideas why this is happening?? or am i missing something..?
> > the same is the case when i replace
> > $a2[0] = 3; with
> > $a1[0] = 3;
> > $x = 3;
> > 
> > Kranthi.
> > 
> 
> $a2[0] was assigned the value of $x or 1, so when you change $a2[0],
> that's all that changes.  You have changed the value 1 to 3. $a1[0] is a
> reference to $x, so if you change $a1[0] it will change $x, but not
> $a2[0] because it is not a reference to $x.
> 
> -- 
> Thanks!
> -Shawn
> http://www.spidean.com
> 
To get the results you expect, you should remove the & from the
assignment, as this is assigning by reference, rather than by value like
Shawn said, or use an & for $a2 as well.


Ash
www.ashleysheridan.co.uk


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