kranthi wrote: > i have this script > > <?php > $x = 1; > $y = 2; > $a1 = array(&$x, &$y); > $a2 = array($x, $y); > $a2[0] = 3; > print_r($a1); > print_r($a2); > ?> > > i am expecting > > Array > ( > [0] => 3 > [1] => 2 > ) > Array > ( > [0] => 3 > [1] => 2 > ) > > > while i m getting > > Array > ( > [0] => 1 > [1] => 2 > ) > Array > ( > [0] => 3 > [1] => 2 > ) > > > any ideas why this is happening?? or am i missing something..? > the same is the case when i replace > $a2[0] = 3; with > $a1[0] = 3; > $x = 3; > > Kranthi. > $a2[0] was assigned the value of $x or 1, so when you change $a2[0], that's all that changes. You have changed the value 1 to 3. $a1[0] is a reference to $x, so if you change $a1[0] it will change $x, but not $a2[0] because it is not a reference to $x. -- Thanks! -Shawn http://www.spidean.com -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
