> -----Original Message----- > From: Chris [mailto:dmagick@xxxxxxxxx] > Sent: Thursday, February 26, 2009 4:16 PM > To: Boyd, Todd M. > Cc: PJ; PHP General list > Subject: Re: Re: catch the error > > > > In examples sent to you, people foolishly replaced your $db var with > > $db_connect ONLY FOR PART OF THE SCRIPT. You've defined your database > > connection as $db_connect in some versions of the source, but then > you > > reference $db (without _connect) in your mysql_select call in that > same > > source. > > > > $db = mysql_connect([option list here]); # <-- this code instantiates > a > > connection > > mysql_select_db([some name], $db); # notice how $db is here? > > $result = mysql_query([some query], $db); # it's here, too! > > > > $db becomes your resource link when you use mysql_connect. That > resource > > link must then be passed to your mysql functions. Otherwise, they > have > > no idea which database connection you are attempting to use. > > RTFM? > > If no connection is specified, the last one is used. > > It is an optional argument (only *really* needed when you have multiple > connections in the same script). RTF E-mail I sent? He had used $db_connect instead of $db. $db_connect hadn't been set to anything. He was specifying a connection, but it was null. Unless it falls back to the last connection used in the case of an empty variable, then this was most likely (read: proven to be) the problem. :p -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
