Hi PJ,
On Thu, Feb 26, 2009 at 17:28, PJ <af.gourmet@xxxxxxxxxxxx> wrote:
> What is wrond with this file? same identical insert works from console
> but not from this file :-(
>
> [snip]
>
> <?
> //include ("lib/db1.php"); // Connect to database
> mysql_connect('biggie', 'user', 'password', 'test');
> $sql1 = "INSERT INTO example (name, age) VALUES ('Joe Blow', '69')";
> $result1 = mysql_query($sql1,$db);
> if (!$result1) {
> echo("<P>Error performing 1st query: " .
> mysql_error() . "</P>");
> exit();
> }
> ?>
I haven't coded in PHP for a long time, but I think that your problem
is in this line:
$result1 = mysql_query($sql1,$db);
Up to that point, $db (that should point to a database link
identifier) is not defined. You probably want to assign the
"mysql_connect" result to that $db variable.
So, I think that you will solve your problem by changing your
"mysql_connect" line FROM the current form:
mysql_connect('biggie', 'user', 'password', 'test');
... TO this one:
$db = mysql_connect('biggie', 'user', 'password', 'test');
Am I right?
Cheers,
Ricardo Dias Marques
lists AT ricmarques DOT net
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