If you mean <p class='something'></p> then this should be okay: $tag_regex=array( '/\<p\>(.*?)\<\/p\> /si' => "$1", '/\<p(\s*)class\=(*.?)\>(.*?)\<\/p\>/si' => "$2" ); $paragraphs=preg_replace(array_keys($tag_regex),array_values($tag_regex),$pa ge); $paragraphs will be the return value $page is the text with all of the tags that you want to stripped If you want, you can try the first value in the array first which detect the <p></p>. I didn't test this, but this should be working since I also use this kind of way to revert the phpbb code into HTML. HTH, Thanks, -----Original Message----- From: Ryan S [mailto:genphp@xxxxxxxxx] Sent: Wednesday, May 07, 2008 10:52 AM To: vester_s Cc: php php Subject: Re: Re: Re[PHP] gex to catch <p>s Hey, <clip> $tag_regex=array( '/\<p(\s*)\>(.*?)\<\/p\> /si' => "$1", '/\<(\s*)(*.?)class\=(*.?)\>(.*?)\<\/(*.?)\>/si' => "$3" ); $paragraphs=preg_replace(array_keys($tag_regex),array_values($tag_regex),$pa ge); I am not sure what tag is that you mean on <class="something">, but in this RE .. it should capture any <p> tags (the first element of the array) and any tags (the second element of the array) that has attribute class on it. </clip> Thanks for replying! Sorry, a bit of a typo there, i meant <p class="something"> I ran your regex but got this warning: Warning: preg_replace() [function.preg-replace]: Compilation failed: nothing to repeat at offset 8 in C:\xampp2\htdocs\ezee\tests\para_regex.php on line 25 I think I ran it wrong, because although i have passed $page i dont know where to pass the replacement texts... Can you give me an example on how to run this or an explanation? Thanks! R ____________________________________________________________________________ ________ Be a better friend, newshound, and know-it-all with Yahoo! Mobile. Try it now. http://mobile.yahoo.com/;_ylt=Ahu06i62sR8HDtDypao8Wcj9tAcJ -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php
