On Thu, Mar 20, 2008 at 12:08:39PM -0400, Rod Clay wrote: > Hello. I am new to php programming, but have spent many years > programming in many other languages, most recently perl (with which > php seems to have much in common!). In every other language I've > worked with there is a way for one program to pass control to > another. However, so far in all of the books and other documentation > I've looked at for php, I cannot find a way for one php program to > pass control to another. Is this possible in php, and, if so, please > let me know how. Thank you. This may be what you are looking for: include('next_program'); exit(); If you do this, you have to keep in mind that all the variables you set in the first program are *still* set in the second. This is useful when your first program needs to choose which of two or more programs to run next depending on its calculations. For example, if your first program does error checking then it might want to run an all_ok program or an edit program. -- "To be without a plan is the true genius and glory of the antislavery movement. The mission of that movement is to preach eternal truths, and to bear witness to everlasting testimony against the giant falsehoods which bewitch and enslave the land." -- Nathaniel Peabody Rogers Rick Pasotto rick@xxxxxxxx http://www.niof.net -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php