Re: Match anything between two " that is not a " except if it is escaped...

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This is for double quotes:
'/"[^"\\\\]*(?:\\\\.[^"\\\\]*)*"/'

this is for single:
'/\'[^\'\\\\]*(?:\\\\.[^\'\\\\]*)*\'/'

i took these from the smarty compiler class.


"mathieu leddet" <mathieu.leddet@xxxxxxxxxxxxxxx> wrote in message 
news:067E44F59025F64BBEC3DB1BD2575392ACFC16@xxxxxxxxxxxxxxxxxxxxxxxxx
Hi everyone,

I am struggling with regular expression trying to match strings
delimited by double quotes, but taking into consideration that \" is not
a string ending character.

-------8<---------------------------------------------------------------
-

$in = 'this is a string : "Hi everyone my name is \"Mathieu\"!" Here is
a second string : "PHP is just perfect"';

// pattern for catching strings between "
$pattern = '#"([^"]*)"#';

// surround matching string with HTML span code to highlight
$replacement = '<b>"${1}"</b>';

// perform the reg exp replacement
$out = preg_replace($pattern, $replacement, $in);

-------8<---------------------------------------------------------------
-

$out contains :
this is a string : <b>"Hi everyone my name is \"</b>Mathieu\<b>"!"</b>
Here is a second string : <b>"PHP is just perfect"</b>

This behaviour is normal considering my pattern (anything between two "
that is not a ").
But I don't know how to get this :
this is a string : <b>"Hi everyone my name is \"Mathieu\"!"</b> Here is
a second string : <b>"PHP is just perfect"</b>

I would like my pattern to express : Anything between two " that is not
a " except if it is escaped.

Thanks for reading me, any help in return is welcome !


--
Mathieu

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