On Jan 15, 2008 11:25 AM, Adam Williams <awilliam@xxxxxxxxxxxxxxxx> wrote: > Thanks, I think I have it: > > $dateexplode = explode("-", $_POST["date_entered"]); > if (!preg_match("/^(\d{2})$/", $dateexplode[0],$data1) || > !preg_match("/^(\d{2})$/", $dateexplode[1],$data2) || > !preg_match("/^(\d{4})$/", $dateexplode[2],$data3)) > { > die ("you have entered an invalid date"); > } > > so if the person enters 01-15-2008 its fine, but 1-15-2008 dies. > Just curious why you won't take 1-15-2008. Once you validate it, you can always assign it to a variable as either a timestamp or a DateTime object and then format it however you want when you display it, send it to a database, or whatever you are doing with the date. FWIW, what you have above will also accept 42-75-2008. Andrew -- PHP General Mailing List (http://www.php.net/) To unsubscribe, visit: http://www.php.net/unsub.php