if (!in_array($component_reference, array(5,17)))
// ...
More compact.
On Oct 18, 2007, at 5:49 PM, "ron.php" <ron.php@xxxxxxxxxxxxxxxxxx>
wrote:
When $component_reference is 5 or 19 I don't want the echo statement
to
output to the screen. What is the correct syntax? What I have
below isn't
working. Thanks for your help. Ron
if ( ($component_reference != "5") OR ($component_reference !=
"19") ) {
echo "<li><a href=\"index.php?request=" . $request . "\">" .
$component_name . "</a>";
}
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