At 4:14 PM -0400 9/19/07, brian wrote:
tedd wrote:
At 11:52 AM -0400 9/17/07, brian wrote:
tedd wrote:
Richard Kurth wrote:
$Campaign_array| = array('0','1','3','5','8','15','25');|
I know that I can find the next recored in a array using next.
What I do not understand is if I know the last number was say 5
how do I tell the script that that is the current number so I
can select the next record
What the next record?
Try:
$array = array('0','1','3','5','8','15','25');
$val = "5";
echo($array[array_search($val, $array)+1]);
Cheers,
tedd
Not quite:
$array = array('0','1','3','5','8','15','25');
$val = "25";
echo($array[array_search($val, $array)+1]);
Notice: Undefined offset: 7 ...
brian
Duh?
You program for that -- you want me to write the entire code?
~sigh~
Grasshopper, the point i was trying to make is that your example
displays what *not* to do with array_search(). Though a wonderful
teaching aid in itself, it falls somewhat short of being a
reasonable solution for the OP.
brian
~sigh~
Sorry to disappoint you master. But I was using array_search() to
search an array -- it seemed like a reasonable thing to do.
So why do you say it's an example of what *not* to do with array_search()?
Please be specific.
Cheers,
tedd
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